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What is the number of total factors for (a^3b^5)^4 if a and b are two different primes?

 Aug 22, 2021
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(a^3b^5)^4 = a^12 * b^20

 

I think the total number of factors is   (12+1)(20*1) = 13*21 = 273

 Aug 23, 2021

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