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How many natural-number factors does N have if N=2^4*3^8*5^2*7^2?

 Jun 4, 2022
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2^4*3^8*5^2*7^2==2 , 2 , 2 , 2 , 3 , 3 , 3 , 3 , 3 , 3 , 3 , 3 , 5 , 5 , 7 , 7>> Total Prime Factors = 16

 

[4+1] x [8+1] x [2+1] x [2+1]==405 divisors.

 Jun 4, 2022

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