If you fall from 22 meters the speed at impact is 20.77m/s(right?)
Someone pls explain how speed of impact is 20.77m/s or if thats not right whats the correct answer and how they worked it out
Equate potential energy at height h, m*g*h, with kinetic energy as you hit the ground, {1/2)m*v^2
(1/2)m*v^2 = m*g*h
v^2 = 2*g*h
v = sqrt(2*g*h)
v = sqrt(2*9.8*22) ≈ 20.77m/s
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