A clock that loses 10 minutes every hour is set correctly at 10:00. What is the correct time when the clock next reads 10:00? Thanks.
+37084 Interesting question...here is my take...
10 o'clock to 10 o'clock is 12 hours ...or 720 minutes
OUr faulty clock only has 50 minutes /hr 720/50 = 14.4 hours
14.4 hours from 10:00 would be real time 12:24
Another way at the REAL 10:00 faulty clock will have lost 10 x 12 = 120 minutes and will be displaying 8:00
at real time 11:00 faulty will display 8:50
12:00 9:40
the faulty clock will need to go 20 more faulty minutes to reach 10:00 20 x 60/50 = 24 more minutes REAL time
will be 12:24
+129840
Well......if we're talking about an analog clock
The clock will lose 1 hour in every 6.......so..........,it will take 72 hours - 3 days - to lose 12......and it will again show "10" at that time
If we're talking about a digital clock, it will take twice as long because it needs to lose 24 hours for the time to be correct.............
+37084 Hey Chris......
I agree that it will take the clock this long TO BE CORRECT again, but the question asked what will the REAL time be when the FAULTY clock next displays 10:00. Yes, I assumed an analog clock (as the question did not specify AM/PM ).
Happy Black Friday!
The ratio of an accurate clock to the faulty clock is: 60/50 =1.2
12 hours past the faulty clock would amount to: 1.2 x 12 =14.4, or 12:24 on the accurate clock.
+118654 A clock that loses 10 minutes every hour is set correctly at 10:00. What is the correct time when the clock next reads 10:00? Thanks.
I decided to do it the super long way :)
| real time | clock time |
| 10 | 10 |
| 11 | 10:50 |
| 12 | 11:40 |
| 1(3 hours) | 12:30(2.5 hours) |
| 2 | 1:20 |
| 3 | 2:10 |
| 4 (6 hours) | 3:00(five hours) |
| 5 | |
| 6 | |
| 7 | |
| 8 | |
| 9 | |
| 10(12 hours) | 8(ten hours) |
| 11 | 8:50 |
| 12 | 9:40 |
| 12+20*6/5=12+24=12:24 | 9:40+20 |
| 12:24 | 10:00 |
| 60 normal time units | 50long time units |
| 60/50 | 1 |
| 6/5 | 1 |
