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What is the whole order of Fibonacci numbers?

 Feb 24, 2016

Best Answer 

 #2
avatar+130466 
+10

The nth Fibonacci number is given by :

 

F(n)  = [ Phi^n  - [-phi]^n ]  / √ 5 

 

Where  Phi  =  [  1 + √5] / 2

 

And phi  =  2 / [ 1 + √5 ]

 

 

cool cool cool

 Feb 24, 2016
 #1
avatar+5265 
+10

I can give you about 10-15 numbers in the sequence.

 

1,1,2,3,5,8,13,21,34,55,89

 

There's 11. Anyone else want to continue on afterwards?

 Feb 24, 2016
 #2
avatar+130466 
+10
Best Answer

The nth Fibonacci number is given by :

 

F(n)  = [ Phi^n  - [-phi]^n ]  / √ 5 

 

Where  Phi  =  [  1 + √5] / 2

 

And phi  =  2 / [ 1 + √5 ]

 

 

cool cool cool

CPhill Feb 24, 2016
 #3
avatar+8262 
+5

Well, this is all about adding the number that is before that number with your answer. 
FOR EXAMPLE:

 

 

1+1=2

 

2+1=3

 

3+2=5

 

5+3=8

 

and so on.

 Feb 24, 2016
 #4
avatar+26396 
+5

What is the whole order of Fibonacci numbers?

 

 

Golden Ratio =φφ=1+52φ=1.61803398875

 

Fibonacci numbers:

fn=φn(1φ)n5

 

Sequence below zero:

fn=(1)n+1fn

n=6543210123456fn=8532110112358

 

laugh

 Feb 25, 2016

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