+0  
 
0
222
2
avatar

fibonnaci numbers to the 43rd digit..what is the exact number for the golden rule to break it down perfectly

 

1 6 6 7 3 5 1 2 8 2 7 1 6 2 2 6 6 3 4 8 6 2 9 3 8 3 7 2 0 5 2 5 0 8 3 5 5 7 4 2 8 2 7

Guest Jan 13, 2015

Best Answer 

 #2
avatar+26625 
+10

Are you asking about the Binet formula?  This gives the n'th standard Fibonacci number as 

 

$$\frac{(1+\sqrt5)^n-(1-\sqrt5)^n}{2^n\sqrt5}$$

 

However, this doesn't reproduce the number you've written (yours lies between the 203rd and 204th standard Fibonacci numbers).

.

Alan  Jan 13, 2015
Sort: 

2+0 Answers

 #1
avatar+85644 
+5

I do not understand your question.....

 

CPhill  Jan 13, 2015
 #2
avatar+26625 
+10
Best Answer

Are you asking about the Binet formula?  This gives the n'th standard Fibonacci number as 

 

$$\frac{(1+\sqrt5)^n-(1-\sqrt5)^n}{2^n\sqrt5}$$

 

However, this doesn't reproduce the number you've written (yours lies between the 203rd and 204th standard Fibonacci numbers).

.

Alan  Jan 13, 2015

11 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details