fibonnaci numbers to the 45 digit

Question

0

999

2

fibonnaci numbers to the 43rd digit..what is the exact number for the golden rule to break it down perfectly

1 6 6 7 3 5 1 2 8 2 7 1 6 2 2 6 6 3 4 8 6 2 9 3 8 3 7 2 0 5 2 5 0 8 3 5 5 7 4 2 8 2 7

Guest Jan 13, 2015

+33658

+10

Best Answer

Are you asking about the Binet formula? This gives the n'th standard Fibonacci number as

$\frac{(1+\sqrt5)^n-(1-\sqrt5)^n}{2^n\sqrt5}$

However, this doesn't reproduce the number you've written (yours lies between the 203rd and 204th standard Fibonacci numbers).

.

Alan Jan 13, 2015

Alan · Answer 1 · 2015-01-13T09:44:14

Are you asking about the Binet formula? This gives the n'th standard Fibonacci number as

$\frac{(1+\sqrt5)^n-(1-\sqrt5)^n}{2^n\sqrt5}$

However, this doesn't reproduce the number you've written (yours lies between the 203rd and 204th standard Fibonacci numbers).

.

CPhill · Answer 2 · 2015-01-13T05:56:34

I do not understand your question.....