How do you solve 2e^-0.07t=8
2e^-0.07t=8 divide both sides by 2
e^ (-.0.07t) = 4 take the Ln of both sides
Ln e^(-0.07 t) = Ln 4 and by a log property we can write
-0.07 t = Ln 4 divide both sides by -0.07
t = Ln 4 / -0.07 ≈ -19.8
