We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
833
1
avatar+95 

Find (2+2i)^8? Write in standard form.

 Mar 12, 2018
 #1
avatar+100529 
+1

(2 + 2i)^8  =

 

r  = √ [ 2^2 + 2^2 ]  =  2√2

 

tan  θ  =  2/2   =  1 

 θ  = pi/4

 

(2 + 2i)^8  =  (2√2)^8* e^(i * 8pi /4 )  =   (2√2)^8 *e^( i * 2pi)  =

 

4096 ( cos 2pi + i * sin (2pi) )  =

 

4096 ( 1 + 0i )  =

 

4096

 

 

cool cool cool

 Mar 12, 2018

23 Online Users

avatar