Find (2+2i)^8? Write in standard form.
(2 + 2i)^8 =
r = √ [ 2^2 + 2^2 ] = 2√2
tan θ = 2/2 = 1
θ = pi/4
(2 + 2i)^8 = (2√2)^8* e^(i * 8pi /4 ) = (2√2)^8 *e^( i * 2pi) =
4096 ( cos 2pi + i * sin (2pi) ) =
4096 ( 1 + 0i ) =
4096