Find 3 consecutive integers such that 3 times the third is equal to the sum of the first and second..how do I solve this?
So, let the integers be n, n+1 and n+2......and we have
3(n+2) = n + n + 1
3n + 6 = 2n + 1 subtract 2n, 6 from both sides
n = -5
n+ 1 = -4
n + 2 = -3
Check
3(-3) = -5 + -4
-9 = -9
