Find 4 consecutive even integers where the product of the two smaller numbers is 72 less than the product of the two larger numbers.​

Let the two smallest  integers =  x  and x + 2

Let the two largest  =  x + 4 , x + 6

So

x(x + 2) + 72  = (x + 4) ( x + 6)       simplify

x^2 + 2x  + 72 =  x^2  + 4x + 6x  + 24      subtract x^2 from both sides and simplify

2x + 72  =  10x  + 24     subtract  24, 2x from both sides

8x  =  48   divide both sides by 8

x = 6

x + 2  =8

x + 4  =10 

x + 6  = 12