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\(\int_1^a(3x^2-6x+3)dx=27\)

Guest Jun 6, 2018

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Best Answer

\(\text{Find } a: \int_1^a(3x^2-6x+3)dx=27\)

After factoring the integrand:	\(\int_1^a3(x-1)^2dx=(x-1)^3\|_1^a=(a-1)^3=27\)
Taking the cube root:	\(a-1=3 \Rightarrow a=\boxed4\)

\(\text{The solution you seek is } a=\boxed4\\ \)

GYanggg Jun 6, 2018

GYanggg · Answer 1 · 2018-06-06T07:49:16

\(\text{Find } a: \int_1^a(3x^2-6x+3)dx=27\)

After factoring the integrand:	\(\int_1^a3(x-1)^2dx=(x-1)^3\|_1^a=(a-1)^3=27\)
Taking the cube root:	\(a-1=3 \Rightarrow a=\boxed4\)

\(\text{The solution you seek is } a=\boxed4\\ \)

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