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Find a 2*2 matrix A such that \(\binom{2 \text{ } 7}{5\text{ } 17}A= \binom{3 \text{ } -2}{4 \text{ } 1}\)

 Jul 8, 2019
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Find a 2*2 matrix A such that       \(\binom{2 \text{ } 7}{5\text{ } 17}A= \binom{3 \text{ } -2}{4 \text{ } 1}\)

 

 

\(\binom{2 \text{ } 7}{5\text{ } 17}^{-1}=\frac{1}{2*17-7*5}\binom{17 \text{ } -7}{-5\text{ } 2}=\binom{-17 \text{ } 7}{5\text{ } -2}\)

 

 

\(A=\binom{-17 \text{ } 7}{5\text{ } -2}\binom{3 \text{ } -2}{4\text{ } 1}=\binom{-23 \text{ } 41}{7\text{ } -12}\)

 Jul 8, 2019

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