Find a 2*2 matrix A such that \(\binom{2 \text{ } 7}{5\text{ } 17}A= \binom{3 \text{ } -2}{4 \text{ } 1}\)
Find a 2*2 matrix A such that \(\binom{2 \text{ } 7}{5\text{ } 17}A= \binom{3 \text{ } -2}{4 \text{ } 1}\)
\(\binom{2 \text{ } 7}{5\text{ } 17}^{-1}=\frac{1}{2*17-7*5}\binom{17 \text{ } -7}{-5\text{ } 2}=\binom{-17 \text{ } 7}{5\text{ } -2}\)
\(A=\binom{-17 \text{ } 7}{5\text{ } -2}\binom{3 \text{ } -2}{4\text{ } 1}=\binom{-23 \text{ } 41}{7\text{ } -12}\)