+4 Find a formula for quadratic function whose graph has its vertex at (7,6) and its y-intercept at y=0
+36916 Vertex form of parabola
y = a (x-7)2 + 6 Sub in the given point 0,0 to calculate 'a'
0 = a (0-7)^2 +6 a + -6/49
y = - 6/49 (x-7)2 + 6 <======== expand for Quadratic Form requested
