1. Form the cross product of u and v:
uxv = (-3i - j + k)x(-3i + 2j + 3k)
→ (-3i)x(-3i) + (-3i)x2j + (-3i)x3k
+ (-j)x(-3i) + (-j)x2j + (-j)x3k
+ kx(-3i) + kx2j + kx3k
→ 9ixi - 6ixj -9ixk + 3jxi -2jxj - 3jxk - 3kxi + 2kxj + 3kxk
Now for cross products we have. ixi = jxj = kxk = 0
ixj = -jxi = k
jxk = -kxj = i
kxi = -ixk = j
So: uxv → 0 - 6k + 9j -3k - 0 - 3i - 3j - 2i + 0
uxv → -5i + 6j - 9k
2. To get the unit vector divide each coefficient by sqrt(5^2 + 6^2 + 9^2) → sqrt(142)
.