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Find all pairs of real numbers (x,y) such that x+y=6 and x^2+y^2=28.

 Nov 5, 2016
 #1
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Find all pairs of real numbers (x,y) such that x+y=6 and x^2+y^2=28.

 

x = 3-sqrt(5) ≈ 0.763932 and y = 3+sqrt(5) ≈ 5.23607

x = 3+sqrt(5) ≈ 5.23607 and y = 3-sqrt(5) ≈ 0.763932

 Nov 5, 2016
 #2
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Find all pairs of real numbers (x,y) such that x+y=6 and x^2+y^2=28.

laugh

 Nov 5, 2016
 #4
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You've gone a little wrong in the second line of your development of y1 and y2 Omi.

 

For y1:  \(6-(3-\sqrt5)\rightarrow3+\sqrt5\) not \(9+\sqrt5\)

 

A similar comment holds for y2.

.

Alan  Nov 6, 2016
 #3
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Omi67:

The two values of "y" are wrong. They do not balance the equations.

 Nov 6, 2016

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