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x/(x^2-4)+1/x+2=3

 Aug 20, 2016
 #1
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x ≈ 0.806063

x ≈ -1.70928

x = 1/3 (2+(8 2^(2/3))/(-5+3 i sqrt(111))^(1/3)+(2 (-5+3 i sqrt(111)))^(1/3)) [COMPLEX]

 Aug 21, 2016
 #2
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\(\dfrac{x}{x^2-4}+\dfrac{1}{x+2}=3\\ x+1(x-2)=3(x^2-4)\\ x+x-2=3x^2-12\\ 3x^2-2x-10=0\\ x=\dfrac{-(-2)\pm\sqrt{(-2)^2-4(3)(-10)}}{2(3)}\\ \;\;=\dfrac{2\pm\sqrt{124}}{6}\\ \;\;=\dfrac{2\pm2\sqrt{31}}{6}\\ \;\;=\dfrac{1\pm\sqrt{31}}{3}\\ \therefore x=\dfrac{1+\sqrt{31}}{3}\text{ OR }x=\dfrac{1-\sqrt{31}}{3}\)

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 Aug 21, 2016

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