+253 Find an equation of the line that satisfies the given conditions. Through (6,1); perpendicular to the line y=4.
+130511 This one's easy......
An equation perpendicular to a line with an equation of y = a is one that has an equation.....x = b
So, if our perpendicular line goes through (6,1)......the equation of this is just x = 6.
Notice, the graph below..... y=4 is a horizontal line where every point has a y value of 4 - no matter what its x value is. And the line x=6 is a vertical line where every point has an x value of 6 - no matter its y value !!! y = 4 is the red line and x = 6 is the blue
+130511 This one's easy......
An equation perpendicular to a line with an equation of y = a is one that has an equation.....x = b
So, if our perpendicular line goes through (6,1)......the equation of this is just x = 6.
Notice, the graph below..... y=4 is a horizontal line where every point has a y value of 4 - no matter what its x value is. And the line x=6 is a vertical line where every point has an x value of 6 - no matter its y value !!! y = 4 is the red line and x = 6 is the blue
