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Find an ordered triple (x,y,z) of real numbers satisfying x ≤ y ≤ z and the system of equations

 

√x + √y + √z = 10

x + y + z = 42

√(xy) + √(xz) + √(yz) = 29

or, if there is no such triple, enter the word "none" as your answer.

 Feb 12, 2021
 #1
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The solution is (x,y,z) = (4,9,25).

 Mar 1, 2025

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