Find constants 
and 
such that
for all 
such that 
and 
. Give your answer as the ordered pair 
.
+130555 This is a partial fraction problem.....getting a common denominator on the right will give us equal denominators on both sides....then, we can set the numerators equal on each side and solve....so we have
x + 7 = A(x+1) + B(x-2) simplify
x + 7 = (A+B)x + (A - 2B) equating co-efficients, we have
A + B = 1
A - 2B = 7 subtract the first equation form the second, and we have
-3B = 6 so B = -2 and using the first equation....A - 2 = 1 ...so A = 3
So, (A, B) = (3, -2)
+130555 This is a partial fraction problem.....getting a common denominator on the right will give us equal denominators on both sides....then, we can set the numerators equal on each side and solve....so we have
x + 7 = A(x+1) + B(x-2) simplify
x + 7 = (A+B)x + (A - 2B) equating co-efficients, we have
A + B = 1
A - 2B = 7 subtract the first equation form the second, and we have
-3B = 6 so B = -2 and using the first equation....A - 2 = 1 ...so A = 3
So, (A, B) = (3, -2)
