+0  
 
0
116
3
avatar

Find DB

 

 Mar 28, 2021
 #1
avatar+91 
0

Let x represent the length of DB.

 

AC =  √(16+ 122) = √400 = 20

 

CB = √(x2 + 122)

 

AB = x + 16 

 

Note that △ABC is right, meaning that AC2 + CB2 = AB2.

Substituting values for AC, CB, and AB, we get:

 

202 + [√(x2 + 122)]2 = (x + 16)2

400 + x2 + 122 = x2 + 32x + 256

544 + x2 = x2 + 32x + 256

544 = 32x + 256

288 = 32x

x = 9

 

Therefore the length of DB is 9.

 Mar 29, 2021
 #2
avatar
0

DB / 12 = 12 / 16

DB = 144 / 16

DB = 9

 Mar 29, 2021
 #3
avatar+1437 
+1

DB = 12(12 / 16)

 Mar 31, 2021

24 Online Users

avatar
avatar