find an equation of the liner through (-78,-56) paralled with the line given by -8+52x+97y=0
+9466 Parallel lines have the same slope. We can find the slope of our line by finding the slope of the line
-8 + 52x + 97y = 0 . Let's get this into slope intercept form. Subtract 97y from both sides.
-8 + 52x = -97y Divide through by -97 .
\(\frac{8}{97}-\frac{52}{97}x=y \) Rearrange.
\(y=-\frac{52}{97}x+\frac8{97}\) When the equation is in this form, we can see that the slope is -\(\frac{52}{97}\) .
So, the equation of the line with a slope of -\(\frac{52}{97}\) that passes through (-78, -56) is.....
y - -56 = -\(\frac{52}{97}\)( x - -78 )
y + 56 = -\(\frac{52}{97}\)( x + 78 ) This is in " point-slope " form. We can get it in slope-intercept form.
y + 56 = -\(\frac{52}{97}\)x - \(\frac{4056}{97}\) Subtract 56 from both sides of this equation.
y = -\(\frac{52}{97}\)x - \(\frac{9488}{97}\)
Here's the graph I used to check this answer: https://www.desmos.com/calculator/ssvwvuf0cb
+9466 Parallel lines have the same slope. We can find the slope of our line by finding the slope of the line
-8 + 52x + 97y = 0 . Let's get this into slope intercept form. Subtract 97y from both sides.
-8 + 52x = -97y Divide through by -97 .
\(\frac{8}{97}-\frac{52}{97}x=y \) Rearrange.
\(y=-\frac{52}{97}x+\frac8{97}\) When the equation is in this form, we can see that the slope is -\(\frac{52}{97}\) .
So, the equation of the line with a slope of -\(\frac{52}{97}\) that passes through (-78, -56) is.....
y - -56 = -\(\frac{52}{97}\)( x - -78 )
y + 56 = -\(\frac{52}{97}\)( x + 78 ) This is in " point-slope " form. We can get it in slope-intercept form.
y + 56 = -\(\frac{52}{97}\)x - \(\frac{4056}{97}\) Subtract 56 from both sides of this equation.
y = -\(\frac{52}{97}\)x - \(\frac{9488}{97}\)
Here's the graph I used to check this answer: https://www.desmos.com/calculator/ssvwvuf0cb
