Find f(11) for f(x) = x^2-9/27-x^3

Find f(11) for f(x) = [x^2-9] / [27-x^3]     factoring first may reduce the work a little

[ (x + 3) (x - 3) ]  /  [  (3 - x ) ( 9 + 3x  + x^2 ) ]  =      factor a negative 1 out of the second factor in the numerator

- [ ( x + 3) (3 - x) ]  / [  (3 - x ) ( 9 + 3x  + x^2 ) ]    =  (3 -x)  "cancels"

- ( x + 3)   / ( x^2 + 3x + 9)

So f(11)   =

- (11 + 3) / ( 11^2 + 33 + 9 )  =

- (14) / (121 + 33 + 9 )  =

- (14) / ( 163)