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Find four consecutive Integers such that the product of the first and the fourth is 22less than the product of - 10 and the third integer.

 Feb 23, 2021
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x-2     x-1     x      x+1  are the four integers

 

(x-2)(x+1)  + 22  =  -10(x)

x^2 -x-2     + 22 = -10x

x^2 +9x +20 = 0

(x+5)(x+4)  = 0       x = -5   or -4

 

-7   -6   -5    -4                  or        -6    -5   -4   -3  

 Feb 23, 2021

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