[x^2 + x - 2 ] / [x^3 + 2x^2 - 3x ] =
[(x - 1)(x + 2)] / [ x ( x + 3) ( x - 1) ] =
[ x + 2 ] / [ x (x + 3) ]
This graph will have vertical asymptotes at x = 0 and x = -3 and a discontinuity - a ("hole") - at x = 1
Here's a graph.....https://www.desmos.com/calculator/zyytyjvhj6
[x^2 + x - 2 ] / [x^3 + 2x^2 - 3x ] =
[(x - 1)(x + 2)] / [ x ( x + 3) ( x - 1) ] =
[ x + 2 ] / [ x (x + 3) ]
This graph will have vertical asymptotes at x = 0 and x = -3 and a discontinuity - a ("hole") - at x = 1
Here's a graph.....https://www.desmos.com/calculator/zyytyjvhj6