Find polar coordinates for the point (2√3,-2)THANK YOU
Polar form is ( r, θ)
r = sqrt [ (2√3)^2 + (-2)^2 ] = sqrt [ 12 + 4] = 4
arctan [ -2/ (2√3) ] = arctan [ -1 / √3 ] = θ = 330°
So, polar form is ( 4, 330° )
BTW....this answer is not unique.....there are infinite possibilities.......