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Find polar coordinates for the point 
(2√3,-2)




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 Apr 18, 2016

Best Answer 

 #1
avatar+129907 
+5

Polar form is ( r, θ)

 

r = sqrt  [ (2√3)^2 + (-2)^2 ]   = sqrt [ 12 + 4]   = 4

 

arctan [ -2/ (2√3) ]  =  arctan [ -1 / √3  ] = θ =  330°

 

So, polar form  is  ( 4, 330° )

 

BTW....this answer is not unique.....there are infinite possibilities.......

 

 

 

cool cool cool

 Apr 18, 2016
 #1
avatar+129907 
+5
Best Answer

Polar form is ( r, θ)

 

r = sqrt  [ (2√3)^2 + (-2)^2 ]   = sqrt [ 12 + 4]   = 4

 

arctan [ -2/ (2√3) ]  =  arctan [ -1 / √3  ] = θ =  330°

 

So, polar form  is  ( 4, 330° )

 

BTW....this answer is not unique.....there are infinite possibilities.......

 

 

 

cool cool cool

CPhill Apr 18, 2016

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