What is the value of \(\sin\left(\frac{5\pi}{2}\right)\)?
Well, first, let's determine the quadrant or quadrantal where the terminal side lies. Rotating counterclockwise by \(\frac{5\pi}{2}\) radians exceeds one revolution, and the terminal side will land on the first quadrantal:
\(\sin(\frac{5\pi}{2})=\sin(\frac{\pi}{2})=1\)