Find sin theta and tan theta if cos theta equals .8 and tan theta is less than 0
Since cos(θ) = adjacent / hypotenuse in a right triangle and
since cos(θ) = 0.8 = 8/10 ---> adjacent = 8 and hypotenuse = 10.
Using the Pythagorean Theorem, opposite = +6 or -6, depending upon the quadrant.
Since tan(θ) < 0, the triangle is found in either the second quadrant or the fourth quadrant.
Since cos(θ) > 0, the triangle is found in either the first quadrant or the fourth quadrant.
Therefore, it must be in the fourth quadrant.
In the fourth quadrant, sin(θ) < 0, making the opposite side -6.
---> sin(θ) = -6/10 = -0.60.
---> tan(θ) = -6/8 = -0.75.
Since cos(θ) = adjacent / hypotenuse in a right triangle and
since cos(θ) = 0.8 = 8/10 ---> adjacent = 8 and hypotenuse = 10.
Using the Pythagorean Theorem, opposite = +6 or -6, depending upon the quadrant.
Since tan(θ) < 0, the triangle is found in either the second quadrant or the fourth quadrant.
Since cos(θ) > 0, the triangle is found in either the first quadrant or the fourth quadrant.
Therefore, it must be in the fourth quadrant.
In the fourth quadrant, sin(θ) < 0, making the opposite side -6.
---> sin(θ) = -6/10 = -0.60.
---> tan(θ) = -6/8 = -0.75.