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Find $t$ such that $(t,5)$ lies on the line through $(0,3)$ and $(-8,0)$

 Jul 10, 2019
 #1
avatar+7824 
+2

Consider the slope:

\(\dfrac{5-3}{t-0} = \dfrac{3-0}{0-(-8)}\\ 16 = 3t\\ t = \dfrac{16}{3}\)

.
 Jul 10, 2019
 #2
avatar+790 
+6

I agree with Max

 

 

Travisio

 Jul 10, 2019
 #3
avatar+790 
+4

:);-):-D:P:-(:'(:-):-*:-$:-\:-[:-!:S:O:-OB-)o_OO_o^O^-.-^_^^﹏^^m^^/^~_~-_--_-||

 Jul 10, 2019

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