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0
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avatar+644 

Find the asymptote of -4x^2 + y^2 - 2y = 3 with positive slope.
 

waffles  Nov 20, 2017
 #1
avatar+87294 
+1

This will be a vertical hyperbola with the following equation

 

(y - 1)^2     -    x^2

______           ___      =     1

    4                   1

 

In the following form

 

(y - k)^2    -   (x - h)^2

______         ______      =  1

   a^2                b^2

 

The center is  ( h, k)   =   (0, 1)

 

The slope of asymptote with the positive slope, m, is    a / b   =  2 / 1  = 2

 

And the equation of this line is

 

y =  m ( x - h) + k  =     2 (x - 0) + 1     =     2x + 1

 

 

cool cool cool

CPhill  Nov 20, 2017

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