find the axis of symmetry and the vertex

y=-2x^2-1   we can write this as

 y= -2(x − 0) ^2 - 1        and in the form   y= a(x − h) ^2   +  k.....     the vertex is at (h, k)  =  (0, -1)    and this parabola is vertical......so he axis of symmetry is   x  = 0

Here is the graph:

@EP, .......... huh?

Where's the mirror?

Oops, I was referring to the upside down parabola. But luckily I found my glasses and noticed the "mirror" myself, .... the -sign at the beginning. Doh!

Sorry for the confusion.