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Find the center of -4x^2 + y^2 - 2y = 3.

waffles  Nov 20, 2017
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-4x^2 + y^2 - 2y  = 3

 

Rewrite as

 

y^2 -2y  - 4x^2  = 3     comlplete the square on y

 

y^2 - 2y + 1  -  4x^2  =  4       factor the frst three terms

 

(y - 1)^2   - 4x^2  = 4       divide through by 4

 

(y - 1)^2      -   x^2              

_______        ____         =      1

    4                  1

 

This is a "vertical" hyperbola.....the center is   (0, 1)

 

 

cool cool cool

CPhill  Nov 20, 2017

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