find the center of x^2+y^2-8y-33=0

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find the center of x^2+y^2-8y-33=0

Guest Jan 13, 2015

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x^2+y^2-8y-33=0 add 33 to both sides

x^2 + y^2 - 8y = 33 complete the square on y

x^2 + y^2 - 8y + 16 = 33 + 16 factor

(x - 0)^2 + (y - 4)^2 = 49

The center of this circle is at (0 , 4) and the radius = 7

CPhill Jan 13, 2015

1⁺⁰ Answers

+130536

+5

Best Answer

x^2+y^2-8y-33=0 add 33 to both sides

x^2 + y^2 - 8y = 33 complete the square on y

x^2 + y^2 - 8y + 16 = 33 + 16 factor

(x - 0)^2 + (y - 4)^2 = 49

The center of this circle is at (0 , 4) and the radius = 7

CPhill Jan 13, 2015

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