Find the circumradius of triangle ABC if AB=BC=29 and AC=40.
Circumradius = product of the sides / (4 * area)
Height = sqrt [ 29^2 - 20^2 ] = sqrt [ 441] = 21
Area = (1/2) (40) ( 21) = 420
Circumradius = 29^2 * 40 / (4* 420) = 841/42 ≈ 20.02
thank you!