Hey guys, i missed a day of lecture and i need help with this problem that is part of my lab. Im not sure how to approach a double. tahnks
r = x ln(x) ln(2)
____ - ____ +
33√x 9
Note that we can write this as :
r = (1/3)x^(2/3) - (1/9)ln(x) + ln (2) so.....
We can use the Power Rule on the first term
And the definition of the derivative of ln(x) on the second term
Note....the third term is a constant...its derivative is 0
So we have.....
dr
__ = (2/9)x^(-1/3) - (1/9)(1/x) =
dx
2 1
____ - ___ =
93√x 9x
[ 2 3√x^2 - 1 ]
_____________
9x