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Hey guys, i missed a day of lecture and i need help with this problem that is part of my lab. Im not sure how to approach a double. tahnks 

 Feb 20, 2018
 #1
avatar+99586 
+1

r  =     x                  ln(x)             ln(2)

        ____     -       ____     +

        33√x                9

 

Note  that we can write this as :

 

r  = (1/3)x^(2/3) -  (1/9)ln(x)  +  ln (2)      so.....

 

We can use the Power Rule on the first term

And the definition of the derivative of ln(x)  on the second term

Note....the third term is a constant...its derivative is  0

 

So we have.....

 

dr

__    =   (2/9)x^(-1/3) - (1/9)(1/x)  =  

dx

 

 

   2                   1

 ____     -       ___        =

 93√x               9x

 

 

[ 2 3√x^2  -  1    ]

_____________

          9x

 

 

 

cool cool cool

 Feb 20, 2018

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