Find the distance between (3,4) and the line 4x+3y+7=0.
We can use a "formula" here
The distance =
l ( 4(3) + 3(4) + 7 ) l / sqrt ( 4^2 + 3^2) =
l ( 31) l / sqrt (25) =
31 / 5 =
6.2 units = the distance