Find the equation of the line containing the perpendicular bisector of (2,18) (-2,-4)
+130511 Find the equation of the line containing the perpendicular bisector of (2,18) (-2,-4)
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OK...we need to find TWO things, here, before even attempting to write an equation - the midpoint of this segment and the slope between the two points.
The midpoint is [(2 -2)/2, (18-4)/2] = [0, 7]
The slope is (-4-18 ) / (-2-2) = -22/-4 = 11/2.....but since we're writing an equation for a perpendicular bisector, we need to take the negative reciprocal of this = -2/11
So....using point-slope from, we have...
y - 7 = (-2/11)(x-0)
y-7 = (-2/11)x
y = (-2/11)x + 7
+130511 Find the equation of the line containing the perpendicular bisector of (2,18) (-2,-4)
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OK...we need to find TWO things, here, before even attempting to write an equation - the midpoint of this segment and the slope between the two points.
The midpoint is [(2 -2)/2, (18-4)/2] = [0, 7]
The slope is (-4-18 ) / (-2-2) = -22/-4 = 11/2.....but since we're writing an equation for a perpendicular bisector, we need to take the negative reciprocal of this = -2/11
So....using point-slope from, we have...
y - 7 = (-2/11)(x-0)
y-7 = (-2/11)x
y = (-2/11)x + 7
