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# Find the equation of the line that contains the point whose coordinates are (3, 1) and has a slope of 3.

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Find the equation of the line that contains the point whose coordinates are (3, 1) and has a slope of 3.

Tiffybean  Nov 3, 2017

#1
+6335
+1

slope  =  (y2 - y1) / (x2 - x1)

Using the points  (3, 1)  and  (x, y)  and a slope of  3 , we get

3  =  (y - 1) / (x - 3)       To get it in slope-intercept form, multiply both sides by  (x - 3) .

3(x - 3)  =  y - 1

3x - 9  =  y - 1              Add  1  to both sides.

3x - 8  =  y

y  =  3x - 8

hectictar  Nov 3, 2017
Sort:

#1
+6335
+1

slope  =  (y2 - y1) / (x2 - x1)

Using the points  (3, 1)  and  (x, y)  and a slope of  3 , we get

3  =  (y - 1) / (x - 3)       To get it in slope-intercept form, multiply both sides by  (x - 3) .

3(x - 3)  =  y - 1

3x - 9  =  y - 1              Add  1  to both sides.

3x - 8  =  y

y  =  3x - 8

hectictar  Nov 3, 2017

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