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$${\mathtt{w}} = {\frac{\left({{\mathtt{z}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{z}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{\left({{\mathtt{z}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}}$$

Guest Jul 9, 2014

Best Answer 

 #1
avatar+26402 
+5

locus

Alan  Jul 9, 2014
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 #1
avatar+26402 
+5
Best Answer

locus

Alan  Jul 9, 2014

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