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$${\mathtt{w}} = {\frac{\left({{\mathtt{z}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{z}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{\left({{\mathtt{z}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}}$$

 Jul 9, 2014

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 #1
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locus

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 Jul 9, 2014
 #1
avatar+33615 
+5
Best Answer

locus

Alan Jul 9, 2014

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