Find the equation of the parabola with focus at the origin and with directrix equation y=-12.
The vertex lies halfway between the focus (0,0) and the point on the directrix given by (0, -12). So, using the mid-point formula, we have......
((0 + 0) / 2 , (0 + (-12)) / 2 ) = ( 0, -6)
So, the equation of the parabola, where a = 1, and the vertex is (h, k) = (0, -6) =
y = a(x - h)2 + k = (x - 0)2 + (-6) = x2 - 6
Here's a graph......https://www.desmos.com/calculator/ixkwz7bips
The vertex lies halfway between the focus (0,0) and the point on the directrix given by (0, -12). So, using the mid-point formula, we have......
((0 + 0) / 2 , (0 + (-12)) / 2 ) = ( 0, -6)
So, the equation of the parabola, where a = 1, and the vertex is (h, k) = (0, -6) =
y = a(x - h)2 + k = (x - 0)2 + (-6) = x2 - 6
Here's a graph......https://www.desmos.com/calculator/ixkwz7bips