+130477 Assuming we're in degrees, we have
sin(345) = sin(300 + 45)....and using sin(A + B) = sinAcosB + sinBcosA, we have
sin300cos45 + sin45cos300 =
(-√3/2)(1/√2) + (1/√2)(1/2) =
-√3/ (2√2) + 1/(2√2) =
[ 1 - √3 ] / (2√2) and rationalizing the denominator, we have
√2 [ 1 - √3] / 4 =
(√2 - √6) / 4
+130477 Assuming we're in degrees, we have
sin(345) = sin(300 + 45)....and using sin(A + B) = sinAcosB + sinBcosA, we have
sin300cos45 + sin45cos300 =
(-√3/2)(1/√2) + (1/√2)(1/2) =
-√3/ (2√2) + 1/(2√2) =
[ 1 - √3 ] / (2√2) and rationalizing the denominator, we have
√2 [ 1 - √3] / 4 =
(√2 - √6) / 4
