Find the exact value of tan((5pi)/6)

Question

0

7460

3

Guest Jul 4, 2015

+118696

+5

Best Answer

$\\tan(\frac{5\pi}{6})\\\\ =-tan(2\pi\;-\;\frac{5\pi}{6})\\\\ =-tan(\frac{\pi}{6})\\\\ =-tan 30^0\\\\ =\frac{-1}{\sqrt3}\\\\ =\frac{-\sqrt3}{3}\\\\$

Melody Jul 5, 2015

Melody · Answer 1 · 2015-07-05T12:42:00

$\\tan(\frac{5\pi}{6})\\\\ =-tan(2\pi\;-\;\frac{5\pi}{6})\\\\ =-tan(\frac{\pi}{6})\\\\ =-tan 30^0\\\\ =\frac{-1}{\sqrt3}\\\\ =\frac{-\sqrt3}{3}\\\\$

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Guest · Answer 2 · 2015-07-04T10:29:40

I assume you are working in radians (and not degrees) -0.57735026919

CPhill · Answer 3 · 2015-07-04T10:36:07

The exact value = -1 / √3 or -√3 / 3 .....{ if you prefer to "rationaloze" the denominator }.......