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Find the exponential function that contains the points (0,7) and (4,112).

 Jan 14, 2020
 #1
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f(x) = L ekx       when x = 0     f(x) = 7   

7 = L ek(0)

L = 7

 

f(x) = 7 ekx         when x = 4     f(x) = 112

112 = 7 ek(4)

ln (112/7)  = k4

k = .69315

 

f(x) = 7 e.69315 x

 Jan 14, 2020

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