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Find the following angles in [0º,300º]
4 tan θ cos2=3 tan θ

 Apr 14, 2016
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4 tan θ cos^2 θ = 3 tan θ       subtract 3 tan θ    from both sides

 

4tan θ  cos^2 θ  - 3 tan θ   = 0      factor out tan θ

 

tan θ  [ 4cos^2 θ - 3]  = 0       set both factors to 0

 

tan θ  = 0    and this happens at  0°  and 180°

 

4cos^2 θ  - 3   = 0     add 3 to both sides

 

4cos^2 θ   = 3      divide both sides by 4

 

cos^2 θ  = 3/4     take ±   square roots of both sides

 

cos θ   =  ± sqrt(3)/2  

 

And the angles that make these two values true  are  30°, 150°, 210° and 330°

 

 

 

cool cool cool

 Apr 14, 2016

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