Compute the definite integral:
integral_log(π/2)^(π/6) 2 e^u du
Factor out constants:
= 2 integral_log(π/2)^(π/6) e^u du
Apply the fundamental theorem of calculus.
The antiderivative of e^u is e^u:
= 2 e^u right bracketing bar _log(π/2)^(π/6)
Evaluate the antiderivative at the limits and subtract.
2 e^u right bracketing bar _log(π/2)^(π/6) = 2 e^(π/6) - 2 e^log(π/2) = 2 e^(π/6) - π:
= 2 e^(π/6) - π - Courtesy of Mathematica 11 Home Edition.
