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# Find the largest $x$ such that $$3\sqrt{3x^2+2x+36}+\sqrt{3x^2+2x-36}=40.$$

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Find the largest x such that $$3\sqrt{3x^2+2x+36}+\sqrt{3x^2+2x-36}=40.$$

Mar 30, 2021

### 1+0 Answers

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not sure how to explain it but the answer is 5

Mar 30, 2021