Find the middle term of (3x^2 - 2y)^6
Help please?
There will be 7 terms in this expansion
The fourth term term is the middle term and is given by:
C(6,3)*(3x^2)^3*(-2y)^3 =
20 * (27x^6) * (-8y^3) =
-4320 x^6 y^3