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Find the middle term of (3x^2 - 2y)^6

 

Help please?

 May 30, 2014

Best Answer 

 #1
avatar+130511 
+8

There will be 7 terms in this expansion

The fourth term term is the middle term and is given by:

C(6,3)*(3x^2)^3*(-2y)^3 =

20 * (27x^6) * (-8y^3)  =

-4320 x^6 y^3

 May 30, 2014
 #1
avatar+130511 
+8
Best Answer

There will be 7 terms in this expansion

The fourth term term is the middle term and is given by:

C(6,3)*(3x^2)^3*(-2y)^3 =

20 * (27x^6) * (-8y^3)  =

-4320 x^6 y^3

CPhill May 30, 2014

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