Find the missing side lengths. Leave your answers as radicals in simplest form.

$\tan60º=\frac{12\sqrt3}{b} \qquad|\tan 60º=\sqrt3 \\~\\ \sqrt3=\frac{12\sqrt3}{b} \\~\\ b\sqrt3=12\sqrt3\\~\\ b=12$

....and....

$\sin60º=\frac{12\sqrt3}{a} \qquad|\sin60º=\frac{\sqrt3}{2}\\~\\ \frac{\sqrt3}{2}=\frac{12\sqrt3}{a} \\~\\ a\sqrt3=(2)12\sqrt3 \\~\\ a=24$