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Find the missing terms in each geometric sequence.

a. 3,___, ___, ___, 768

b. ___,___,144,___,___,___,9

 Mar 22, 2016
 #1
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a. 3,___, ___, ___, 768

 

768 = 3r5-1   divide both sides by 3

 

256  = r4     take the 4th root of each side

 

4  = r

 

So ....terms 2 - 4 are given by : 

a2  = 3(4)2-1  = 3(4)1 =   12

a3  = 3(4)3-1 = 3(4)2  = 48

a4  = 3(4)4-1= 3(4)3 = 192      

 

 

 

b. ___,___,144,___,___,___,9

 

 

 

9  =     a1(r)6     (1)

144  = a1(r)2     (2)

 

Divide (1) by (2)   and we have

 

9/144  = r4    →    1/16  = r4    take the 4th root of both sides  →  r = 1/2

 

So ....   using (1)

 

9 = a1 (1/2)6

 

9 = a1 (1/64)    multiply both sides by 64

 

576  = a1     and each successive term is 1/2 of the previous one.....

 

So......term 2  =  576/2  = 288

 

And terms  4 - 6  are     72, 36, 18

 

 

cool cool cool

 Mar 22, 2016

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