+0  
 
0
161
1
avatar

Find the non-zero value of $c$ for which there is exactly one positive value of $b$ for which there is one solution to the equation $x^2 + \left(b + \frac 1b\right)x + c = 0$

 Jul 11, 2020
 #1
avatar
0

Completing the square, the quadratic has a unique root when it is x^2 + 4x + 4 = 0.  So c = 4.

 Jul 11, 2020

10 Online Users

avatar