Find the number of all possible basketball teams (5 players) from a squad of 12 men, each of whom is versatile enough to play any position.
+118723 Your username does not inspire a lot of confidence failed.
Your method is reasonable but it would only be correct if the order of selection mattered and i don't think that it does in this case.
The answer is 12C5 = $${\left({\frac{{\mathtt{12}}{!}}{{\mathtt{5}}{!}{\mathtt{\,\times\,}}({\mathtt{12}}{\mathtt{\,-\,}}{\mathtt{5}}){!}}}\right)} = {\mathtt{792}}$$
this is
$$\frac{12*11*10*9*8}{5*4*3*2*1}$$
So first you select your 5 players just as you did.
but then you think about how many ways those 5 players can be ordered. And you divide by this number.
does this make sense?
+2 its (12*11*10*9*8) as there is only 5 slots for players. and you chose from 12 different people. as you chose one you can next time choose from 11, 10, 9, 8...
+118723 Your username does not inspire a lot of confidence failed.
Your method is reasonable but it would only be correct if the order of selection mattered and i don't think that it does in this case.
The answer is 12C5 = $${\left({\frac{{\mathtt{12}}{!}}{{\mathtt{5}}{!}{\mathtt{\,\times\,}}({\mathtt{12}}{\mathtt{\,-\,}}{\mathtt{5}}){!}}}\right)} = {\mathtt{792}}$$
this is
$$\frac{12*11*10*9*8}{5*4*3*2*1}$$
So first you select your 5 players just as you did.
but then you think about how many ways those 5 players can be ordered. And you divide by this number.
does this make sense?
